Question

beserta caranya yaa kak​

Answer 1

Jawab:

Penjelasan dengan langkah-langkah:

Materi   = Pythagoras , trigonometri

Tingkat = SMP

3. a = [tex]\sqrt{(4\sqrt{3})^2-(2\sqrt{2})^2}[/tex]

     = [tex]\sqrt{48-8}[/tex]

     = [tex]\sqrt{40}[/tex]

     = [tex]\sqrt{4\times10}[/tex]

     = 2[tex]\sqrt{10}[/tex] (A)

4. segitiga siku siku 90,45,45

[tex]\frac{16}{\sin 90^{\circ}} =\frac{x}{\sin 45^{\circ}}[/tex]

[tex]x = \sin 45^{\circ}\times\frac{16}{\sin 90^{\circ}}[/tex]
[tex]x = \frac{\sqrt{2} }{2}\times \frac{16}{1}[/tex]

x = 8√2 (C)

5. ralat soal 15 ⇒ 25

(3x)²+(4x)²=25²

9x²+16x²=625

25x²=625

   x²=625/25

   x²=25

   x=√25

   x=5(D)

6. Gunakan aturan sinus , lihat dalam gambar

[tex]\frac{AD}{\sin 60^{\circ}}=\frac{BD}{\sin 30^{\circ}}[/tex]

AD = [tex]\sin 60^{\circ} \times \frac{4}{\sin 30^{\circ}}[/tex]

AD = [tex]\frac{\sqrt{3}}{2} \times \frac{4}{\frac{1}{2}}[/tex]

AD = [tex]4\sqrt{3}[/tex]

selanjutnya cari AC

AC = [tex]\sqrt{2(4\sqrt{3})^2}[/tex]

AC = 4√6

AC ≈ 9,8 (C)