Question

Besarnya [OH^-] dalam 10 ml larutan yang mengandung 8 gram amonium nitrat adalah.....
(Kb NH4OH = 10^-5, Ar : N = 14, O = 16, H = 1)

Answer 1

V=10 ml
kb= 10^-5
mr NH4OH= 35
gr NH4NO3= 8 GR

H+= √KW/KB X gr/mr x1000/ v

H+= √KW/KB X gr/mr x1000/ v
H+= √10^-14/10^-5 X 8/80 x 1000/10
H+= √10^-9 X 10
H+=√10^-8
H+= 10^-4

OH-= KW /H+
OH-= 10^-14/10^-4
OH-= 10^-10