Besarnya kalor yang dihasilkan kumparan kawat 270 ohm tiap jam, bila di hubungkan pada tegangan 125 volt adalah.....
A) 25 kkal.
B)50 kkal.
C) 75 kkal.
D) 100 kkal.
A) 25 kkal.
B)50 kkal.
C) 75 kkal.
D) 100 kkal.
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W = P . t
W = V^2/R . t
W = 125^2/270 . 3600
W = 208333 J × 0,24 kal = 50000 kal = 50000 : 1000 kkal = 50 kkal
Jawaban: B
Q = V²/R . t
Q = 125² /270 . 3600
Q = 57,87 . 3600
Q = 208333,333 = 50.000 calorie = 50 kKal