Question

Berdasarkan gambar diatas tentukan.
A. nilai X
B. panjang CF dan FB!
C. panjang DE dan AE!

Answer 1

A)
EF = (DC.FB + AB.CF)/(CF+FB)
13 = ( 10(x) + 15(x+1)) /(x+1+x) 
13 = (10x +15x +15)/(2x+1)
13(2x+1) = 25x + 15
26x + 13 = 25x + 15
26x - 25x = 15- 13
x = 2

b)
CF = x+1 = 3
FB = x = 2

c)
DE =x +2 = 4

EF = ( DC. EA + AB. DE ) /(DE+EA)
13 = ( 10(EA) + 15(4))/ (4+EA)
13 = (10 EA + 60) / (4 + EA)
13(4 + EA)  = 10 EA + 60
52 + 13 EA = 10 EA + 60
13 EA - 10 EA = 60- 52
3 EA = 8
EA = 8/3