Penjelasan:
jarak bayangan? (s’)
maka kita cri dlu jarak fokus
f = r ÷ 2
f = 20 ÷ 2
f = 10 cm
nah, cari jarak bayangan
1/f = 1/s + 1/s’
1/s’ = 1/f - 1/s
1/s’ = 1/-10 - 1/2,5
1/s’ = -1-4/10
1/s’ = -5/10
1/s’ = -1/2
s’ = -2
maka, jarak bayangan nya adalah -2
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Penjelasan:
jarak bayangan? (s’)
maka kita cri dlu jarak fokus
f = r ÷ 2
f = 20 ÷ 2
f = 10 cm
nah, cari jarak bayangan
1/f = 1/s + 1/s’
1/s’ = 1/f - 1/s
1/s’ = 1/-10 - 1/2,5
1/s’ = -1-4/10
1/s’ = -5/10
1/s’ = -1/2
s’ = -2
maka, jarak bayangan nya adalah -2