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suhu kamar = 25 C = 298 K
Tekanan = 1 atm = 10^5 Pa
R = 8,314 J / mol K
pV = n R T
10^5 x V = m/M x R x 298
10^5 V = 1/4 x 8,314 x 298
V = 6,194 x 10^-3 m^3 = 6,194 L