NaOH = basa kuat
mb = 0,4 M
pH .. ?
[OH-] = x . mb
[OH-] = 1 . 0,4
[OH-] = 4 .10-¹
pOH = - log [OH-]
pOH = - log 4 .10-¹
pOH = 1 - log 4
pH = 14 - pOH
pH = 14 - ( 1 - log 4)
pH = 14 - 1 + log 4
pH = 13 + log 4
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Diketahui :
NaOH = basa kuat
mb = 0,4 M
Ditanya :
pH .. ?
Dijawab :
[OH-] = x . mb
[OH-] = 1 . 0,4
[OH-] = 4 .10-¹
pOH = - log [OH-]
pOH = - log 4 .10-¹
pOH = 1 - log 4
pH = 14 - pOH
pH = 14 - ( 1 - log 4)
pH = 14 - 1 + log 4
pH = 13 + log 4