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m = 3x10³ kg
Q = 90 J
kalor jenis baja (c) = 450
Ditanya : ΔT ?
Jawab :
Q = m x c x ΔT
90 = (3x10³) x 450 x ΔT
90 = 135x10⁴ x ΔT
ΔT = 15 x 10³ °C