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[tex]\begin{aligned} a &= \sqrt{146 - 11^2} \\&= \sqrt{146 - 121} \\&= \sqrt{25} \\&= \boxed{\bold{\underline{5}}} \end{aligned}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 08 - 07 - 2023}}[/tex]
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Teorema Pythagoras
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[tex]\begin{aligned} a &= \sqrt{146 - 11^2} \\&= \sqrt{146 - 121} \\&= \sqrt{25} \\&= \boxed{\bold{\underline{5}}} \end{aligned}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 08 - 07 - 2023}}[/tex]