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V = 2 liter
T = 27°C = 300°K
R = 8,31 x 10³ J/kmol K
PV = nRT
10⁵.2=n.8,31 x 10³.3 x 10²
2.10⁵ = 24,93 x 10⁵ . n
n = 2.10⁵/24,93 x 10⁵
= 0,08 mol