Question

Berapakah kuat arus(I) yang mengalir tersebut..?

Answer 1

1/Rp = 1/R1 + 1/R2
1/Rp = 1/8 + 1/8
1/Rp = 8 + 8/64
1/Rp = 64/16 = 4

= 3 + 2 + 4 + 1 = 10

kuat arus (I) = V / r
= 24 / 10
= 2,40 A

jadi, jawabnnya ( B )

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