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konsentrasi (Molaritas) = massa/massa molar x 1000/volume(ml)
= 1 gram/40 gram/mol x 1000/250 ml
= 1/40 mol x 4/ml
= 1/10 mol/ml
= 0,1 mol/ml (0,1 M)
massa NaOH = 1 gr
volume = 250 mL = 0,25 liter
M = ?
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mol (n) = massa / Mr
n = 1 gr / 40
n = 1/40 mol
M = n / volume
M = (1/40) mol / 0,25 liter
M = 0,1 M