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Verified answer
LarutanKimia XI
Dik
Massa zat terlarut NaCl = 5,85 gram
Mr NaCl = 58,5
Volum larutan = 100 ml
Dit
Konsentrasi dalam Molaritas
Jaw
Molaritas
M = { [massa NaCl] / Mr } x [1000/volum larutan ml]
M = [5,88/58,5] x [1000/100]
M = 0,1 x 10
Diperoleh konsentrasi sebesar 1 molar atau ditulis 1 M