Berapakah kelarutan AgCl jika Ksp AgCl = 2,5 x 10 ^-5........ a 5 x 10^-3 b 2,5 x 10^-4 c 2,5 x 10^-3 d 2,5 x 10^-5 e 2,5 x 10^-4 bantu pakai cara yyaaaaa
LindaPSP
Agcl = ag + cl s s s ksp=[ag] [cl] s s = s² 2,5 . 10^-5 = s² √25. 10^-4 = s s = 5 . 10^-2
s s s
ksp=[ag] [cl]
s s
= s²
2,5 . 10^-5 = s²
√25. 10^-4 = s
s = 5 . 10^-2