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Q = 0,25 . 4200 . (100-80)
Q = 21000 J
Q = 21 kJ
m=250 g =0,25 kg
t1=80°C
t2=100°C→Δt=t2-t1 = 100-80=20°C
c air = 4.200 J/kg°C
Ditanya:Q=....?
Jawab:
Q= m.c.Δt
Q=0,25 kg . 4.200 J/kg°C. 20 °C
Q=21.000 J.