berapa mol dari dari 12 gram sukrosa
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Penjelasan:
diketahui 12 gram (massa/gr)
ditanya berapa mol?
jawab : rumus kimia sukrosa C12H22O11
c = 12
h = 1
o = 16
C12H22O11 = ( 12 × Ar C ) + ( 22 × Ar H ) + ( 11 × Ar O )
= ( 12 × 12 ) + ( 22 × 1 ) + ( 11 × 16 )
= 144 + 22 + 176
= 212
mencari mol = massa ÷ mr
= 12 gr ÷ 212
= 0,056 mol