Berapa luas yang di arsir??.... Question from @teguhgalih

October 2018 2 18 Report

Berapa luas yang di arsir??

qqqqq1 Pertama cari L segitiganya,
L = 1/2 X a X t
= 1/2 X 12 X 5
= 30cm²

Cari L ppanjang - L 1/2lingkaran,
L = p X l
= 19 X 7 (dikurangi dengan 1/2 lingkaran)
= 133cm²

L = phi X r²
= 22/7 X 7² (karena dah dibagi 2)
= 154cm²
= 77cm²

= 133 - 77
= 56cm²

L diarsir = L segitiga + L di atas
= 30 + 56
= 86cm²

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qqqqq1 maaf agak lupa kalo di min

fanostaa $$\begin{align}L1&= p\times l\\
&= 19 \times 7\\
&= 133\ cm^2\\
L2&= \frac{1}{2} \times \pi \times r^2\\
&= \frac{1}{2} \times \frac{22}{7} \times 7^2\\
 &= \frac{11}{7} \times 49\\
&= 77\ cm^2\\
L3&= \frac{1}{2} \times a \times t\\
&= \frac{1}{2}\times 12 \times 5\\
&= \frac{1}{2} \times60 \\
&= 30\ cm^2\\\\
L_{arsir}&= L1-L2+L3\\
 &= 133-77+30\\
&= 86\ cm^2 \end{align}$

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