Question

Berapa konsentrasi ion H+ asam lemah dari CH3COOH 0,004 M (Ka=1x10-5)?

Answer 1

H+= √ka x Ma
H+ = √1x10-5 x 4x10-3
H+ = √4x10-8
H+ = 2x10-4

Answer 2

H+ = √Ka.Ma
H+ = √10-5 x 4.10-3
H+ = √4.10-8
H+ = 2.10-4

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