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c = 4.200 J/kg
ΔT = 120 - (-20) = 140°C
- Ditanya : Q ... ?
- Jawab :
Q = m × c × ΔT
= 5 × 4.200 × 140
= 2.940.000 J
= 2.940 kJ.
m = 5 kg
c = 4200 J/kg
ΔT = - 20°C
ta = 120°C
Ditanyakan : Q.....?
Penyelesaian :
Q1 = m . c . ΔT
= 5 . 4200 . 20°C
= 420000
Q2 = m c ΔTa
= 5 . 4200 . 120
= 2520000
Q total = Q1 + Q2
= 420000 + 2520000
= 2940000 J