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(2x + y)³
= (2x + y) (2x + y) (2x + y)
= (4x² + 2xy + 2xy + y²) (2x + y)
= (4x² + 4xy + y²) (2x + y)
= 8x³ + 4x²y + 8x²y + 4xy² + 2xy² + y³
= 8x³ + 12x²y + 6xy² + y³
cara II :
(2x + y)³
= 1(2x)³(y)⁰ + 3(2x)²(y)¹ + 3(2x)¹(y)² + 1(2x)⁰(y)³
= 1(8x³)(1) + 3(4x²)(y) + 3(2x)(y²) + 1(1(y³)
= 8x³ + 12x²y + 6xy² + y³
mau pakek cara mana aja hasilnya akan tetap sama,,