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Verified answer
Kelas 10 MatematikaBab Logaritma
^ = pangkat
^xlog (6 - x) >= 2
6 - x >= x²
-x² - x + 6 >= 0
x² + x - 6 <= 0
(x + 3) (x - 2) <= 0
x + 3 >= 0
x >= -3
-3 <= x
x - 2 <= 0
x <= 2
-3 <= x <= 2
syarat
x > 0
6 - x > 0
x - 6 < 0
x < 6
Penyelesaiannya
0 < x <= 2