Question

Berapa gram seng sulfat 0.02M sebanyak 1000 mL?

Answer 1

Seng sulfat : ZnSO4
Mr : 161
n : M x V : 0,02 x 1 liter : 0,02 mol
massa : 0,02 mol x 161 : 3,22 gram

Answer 2

N ZnSO4 = M x V = 0,02 x 1 = 0,02 mol
massa = n x Mr = 0,02 x 161,3 = 3,226 gram