Berapa gram H2SO4 yang diperlukan untuk membuat 500 g larutan 0.1 m(molalitas)
NCH
M = massa zat terlarut : Mr zat terlarut x 1000 : massa pelarut m = gr H2SO4 : 98 x 1000 : (500 - gr H2SO4) 0,1 = X : 98 x 1000 : (500 - X) 0,1 = 1000X : (49000 - 98X) 4900 - 9,8X = 1000X 4900 = 1000X + 9.8X 4900 = 1009.8X X = 4900 : 1009.8 X = Massa H2SO4 = gr H2SO4 = 4,9 gram
m = gr H2SO4 : 98 x 1000 : (500 - gr H2SO4)
0,1 = X : 98 x 1000 : (500 - X)
0,1 = 1000X : (49000 - 98X)
4900 - 9,8X = 1000X
4900 = 1000X + 9.8X
4900 = 1009.8X
X = 4900 : 1009.8
X = Massa H2SO4 = gr H2SO4 = 4,9 gram