Question

Berapa fraksi mol methanol dalam larutan air yang mengandung 80% methanol

Answer 1

Metanol 80%
diket gram metanol (gt) = 80gr
gram air (gp) = 100-80 = 20 gr
mol t = 80/32 = 2.5 mol
mol p = 20/18 = 1.1 mol
Xt = nt / (nt + np )
= 2.5 / ( 2.5 + 1.1 )
= 2.5 / 3.6 = 0.69

Answer 2

Metanol 80% = 80 gram
Air 20% = 20 gram

mol metanol = gr/Mr=80/32=2,5 mol
mol Air = gr/Mr = 20/18 = 1,1 mol
mol larutan = 2,5 + 1,1 = 3,6 mol

 fraksi mol methanol dalam larutan air