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m = 100 gram = 0,1 kg
ΔT = 40 - 10 = 30 derajatC
c alkohol = 2400 J/kgderajatC
Q = m . c . ΔT
Q = 0,1 . 2400 . 30
Q = 7200 J
Δt = t₁ - to
= 40°C - 10°C
= 30°C
c = 2400 J/kg °C
Ditanyakan : Q
Penyelesaian : Q = m . c . Δt
= 0,1 . 2400 . 30
= 7200 J