permutasi
n = 8
r= 4
1 orang selalu duduk dikursi tertentu
banyak = 8-1 = 7
sisa kursi = 4 -1 = 3
banyak cara= 7P3 = 7x 6 x 5= 210
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permutasi
n = 8
r= 4
1 orang selalu duduk dikursi tertentu
banyak = 8-1 = 7
sisa kursi = 4 -1 = 3
banyak cara= 7P3 = 7x 6 x 5= 210