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sehingga,
(3+√5)(3-√5)
= 3²-(√5)²
= 9 - 5
= 4
substitusikan nilai (3+√5)(3-√5) = 4 tsb ke persamaan semula
menjadi
6(3+√5)(3-√5) per (2+√6)
= 6.4 per (2+√6)
= 24 per (2+√6)