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\frac{10y}{y x^{2} -3y-18} : \frac{5y}{4y-24} = \frac{10y}{y x^{2} -3y-18} * \frac{4y-24}{5y} = \frac{2(4y-24)}{y x^{2} -3y-18} = \frac{8(y-6)}{(y+3) (y-6)} = \frac{8}{y+3}
hasilnya 8 per y+3