Question

bentuk kuadrat sempurna dari x²—6x+8=0 adalah.. ​

Answer 1

Verified answer

Jawaban:

x²-6x+8=0

x²-6x = -8

x²-6x+(-3)² = -8 + (-3)²

(x-3)² = -8 + 9

(x-3)² = 1

x-3 = ±√1

x-3 = ±1

x = 3±1

x1 = 3-1 = 2 v x2 = 3+1 = 4

hp{2,4}