Question

Bentuk fungsi dari pasangan berurutan (2,8) (3,9) (4,10) (5,11) (6,12) adalah...

Answer 1

F(x)=2x+b=8
f(x)=3x+b=9
____________-
-x =-1
x =1

2x+b=8
2(1)+b=8
2+b=8
b=8-2
b=6

jadi,, f(x)= x+6

Answer 2

F(x) = 2x + b = 8
f(x) = 3x + b = 9
-
————————
-x = - 1
x = 1

2x + b = 8
2(1) + b = 8
2 + b = 8
b = 8-2
b = 6 Jadi f(x) = x + 6