Question

Benda tingginya 3 cm diletakkan di depan lensa cekung pada jarak 8 cm. jika jarak fokus lensa 24 cm, tentukan : jarak bayangan!

Answer 1

1/24 = 1/8 + 1/s'
1/24 - 3/24 = 1/s'
-2/24 = 1/s'
s' = -12 cm

Answer 2

Dik: ho= 3cm So:8 cm F= 24 cm Dit: si? Jawab 1/si = 1/f - 1/so = 1/24-1/8 = 1-3/24 = -2/24 = -12