Question

Benda tersebut terbentuk dari kerucut dan tabung. luas permukaan bangun tersebut adalah...
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Answer 1

Jawabanya B.

semoga bermanfaat

Answer 2

d = 12 cm

tt = 12 cm

r = (1/2 × d) cm

r = (1/2 × 12) cm

r = 6 cm

tk = (20 - 12) cm

tk = 8 cm

s^2 = r^2 + tk^2

s^2 = 6^2 + 8^2

s^2 = 36 + 64

s^2 = 100

s = V100

s = 10 cm

L permukaan bangun

= (1/4 × phi × d^2) + (phi × d × tt) + (phi × r × s)

= (1/4 × phi × 12 × 12) + (phi × 12 × 12) + (phi × 6 × 10)

= 36 phi + 144 phi + 60 phi

= 240 phi cm^2 (b)