Question

Benda setinggi 5cm terletak 5 cm di depan lensa cekung yang berdioptri -5 dioptri. Tinggi bayangannya adalah

Answer 1

Diket:
lensa cekung
h = 5cm
s = 5cm
P = -5 dioptri
Dit: h'....?
f = -1/5
f = -0,2 m = -20cm
,
1/s' = -1/f - 1/s
1/s' = -1/20 - 1/5
1/s' = -1/20 - 4/20
1/s' = -5/20
s' = -20/5
s' = -4cm
,
I s'/s = h'/h I
4/5 = h'/5
h' = (5x4)/5
h' = 4 cm
tinggi bayangan 4cm

Answer 2

Diketahui:
lensa cekung: h = 5cm, s = 5cm, P = -5 dioptri
Ditanyakan: h'=...
f = -1/5
f = -0,2 m = -20cm
,
1/s' = -1/f - 1/s
1/s' = -1/20 - 1/5
1/s' = -1/20 - 4/20
1/s' = -5/20
s' = -20/5
s' = -4cm
,
I s'/s = h'/h I
4/5 = h'/5
h' = (5x4)/5
h' = 4 cm
Jadi, tinggi bayangannya adalah 4 cm

semoga membantu:)