Question

Benda diletakkan 4cm di depan cermin,jika jarak fokus 6cm.tentukan
a.jarak bayangan
b.perbesaran bayangan
c.sifat bayangan

Answer 1

A. 1/f (fokus) = 1/s' (bayangan) + 1/s (benda)
1/6 = 1/s' + 1/4
1/s' = 1/4 - 1/6
1/s' = 3/12 - 2/12
1/s' = 1/12
s' = 12 cm

M = s'/s
M = 12/4
M = 3 kali

Sifat = maya, tegak, diperbesar

Semoga membantu :)