Jawaban:
lensa cembung
f = 10 cm
s = 20 cm ← ruang 2
perbesaran
m = f / (s - f)
m = 10 / (20 - 10)
m = 3 kali ✔️
jarak bayangan
s' = m s
s' = 3 • 20
s' = 60 cm ✔️
(ruang 3)
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Jawaban:
lensa cembung
f = 10 cm
s = 20 cm ← ruang 2
perbesaran
m = f / (s - f)
m = 10 / (20 - 10)
m = 3 kali ✔️
jarak bayangan
s' = m s
s' = 3 • 20
s' = 60 cm ✔️
(ruang 3)