Jawab:
P(x,y)
x=5 >>> P'(2h-x,y)
P'(2(5)-x,y)
: P'(10-x,y)
: X'=10-x. X=10+x
Y'=y. Y=-y
Substitusi kan
X=-2y²+3y
10+x=-2(-y)²+3(-y)
10+x=2y²-3y
x= 2y²-3y-10
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawab:
P(x,y)
x=5 >>> P'(2h-x,y)
P'(2(5)-x,y)
: P'(10-x,y)
: X'=10-x. X=10+x
Y'=y. Y=-y
Substitusi kan
X=-2y²+3y
10+x=-2(-y)²+3(-y)
10+x=2y²-3y
x= 2y²-3y-10