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x' = x + 2 -----> x = x' - 2
y' = y - 3 -----> y = y' + 3
substitusi ke persamaan garis :
x - 2y - 3 = 0
(x'- 2) - 2(y' + 3) - 3 = 0
x' - 2 - 2y' - 6 - 3 = 0
x' - 2y' - 11 = 0
jadi hasil bayangannya adalah x - 2y - 11 = 0