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Dik. barisan deret geometri : u3 = 24 & u6 = 192.Dit. U8?
Jawab...
U6 = a x r⁵ = 192
U3 = a x r² = 24
----------------------- (:)
@ r³ = 8
@ r = 2
a :
a x r² = 24
a x (2)² = 24
a x 4 = 24
a = 24/4
@ a = 6
U8 = a x r⁷
U8 = 6 x (2)⁷
U8 = 6 x 128
U8 = 768
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