Question

Barisan Geometri
1.U10:3,9,27,.......
2.U12:7,10,13...

Answer 1

1) a = 3
   r = 9/3 = 3
  U10 = ar^9
         = 3(3)^9
         = 3^10

2) a = 7
b = 10 - 7 = 3
U12 = a + 11b
       = 7 + 11(3)
       = 40

Answer 2

No. 1
a = 3
r = 9/3 = 3

U10 = a.r^9 = 3. 3^9 = 59049

No. 2

a = 7
b = 10-7 = 3

U12 = a+(n-1)b = 7+(11)3 = 7+33 = 40

Good Luck! :D