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2k+25,9-k,3k+7
k=2
3k+7,-9,-20,-31,dst
b = (3k+7) - (9-k)
b = 4k - 2
lalu masukan b ke u3 untuk mencari k,
U3 = a + 2b
3k + 7 = (2k + 25) + 2(-3k - 16)
3k + 7 = -4k - 7
7k = -14
k = -2
lalu cari suku berikutnya,
U4 = a + 3b
U4 = (2k + 25) + 3 (4k - 2)
U4 = (2k + 25 + 12k - 6)
U4 = 14k + 19
U4 = 14 (-2) + 19
U4 = -28 + 19
U4 = -9