Odpowiedź:
∡ADB = 90°
∡ABC = ∡BAC = α
∡BAD = 180° - (α + 90°) = 180° - α - 90° = 90° - α
∡ACB = 180° - 2α
∡BAD : ∡ACB = (90° - α)/(180° - 2α) = (90° - α)/2(90° - α) = 1/2 c.n.u
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Odpowiedź:
∡ADB = 90°
∡ABC = ∡BAC = α
∡BAD = 180° - (α + 90°) = 180° - α - 90° = 90° - α
∡ACB = 180° - 2α
∡BAD : ∡ACB = (90° - α)/(180° - 2α) = (90° - α)/2(90° - α) = 1/2 c.n.u