Odpowiedź:
[tex]\displaystyle y=log_3(x^{2} +2x-24)\\x^{2} +2x-24 > 0\\\Delta =4+4*24=100\qquad \sqrt{\Delta } =10\\x_1=\frac{-2+10}{2} =4\quad x_2=\frac{-2-10}{2} =-6\\D=(-\infty,-6)\cup(4,+\infty)[/tex]
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Odpowiedź:
[tex]\displaystyle y=log_3(x^{2} +2x-24)\\x^{2} +2x-24 > 0\\\Delta =4+4*24=100\qquad \sqrt{\Delta } =10\\x_1=\frac{-2+10}{2} =4\quad x_2=\frac{-2-10}{2} =-6\\D=(-\infty,-6)\cup(4,+\infty)[/tex]