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a) CnH2n+2=84u
12n+2n+2=86
14n=84
n=6
C6H14.......CH3-(CH2)4-CH3......heksan
b)CnH2n+2=128u
12n+2n+2=128
14n=126
n=9
C9H20.......CH3-(CH2)7-CH3......nonan
12) mC6H14=72u+14u=86u
%C = (72/86)*100% = 83,7%
%C = (14/86)*100% = 16,3%
13) mC8H18=96u+18u=114u
mC : mH = 96 : 18 = 16 : 3