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*Volume = 100 mL = 0,1 L
*pH = 11 --> [OH-] = 10^-3
*Mr NaOH = 40 gram/mol
*Massa NaOH = ... gram ?
NaOH ⇔ Na+ + OH-
10^-3 10^-3
*M = n / V (L)
n = 10^-3 Molar x 0,1 L
= 10^-4 mol
*n = g/Mr
g = 10^-4 mol x 40 gram/mol
= 0,04 gram NaOH