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b = 3
n = 17
Sn = 1/2 n (2a + (n-1)b)
S17 = 1/2 . 17 (2.10 + (17-1)3)
= 1/2 . 17 (20 + (16)(3))
= 1/2 . 17 (20 + 48)
= 1/2 . 17 (68)
= 34 . 17
= 578 kursi