Galladeaviero
A) misal (√3)^x = a --> x = √3'log a dengan a> 0 7 a - a^2 = - 18 a^2 - 7a - 18 = 0 (a-9)(a+2) = 0 a = 9 atau a= -2 (TM) x = √3'log 9 x= (3^1/2)'log 3^2 x = (2) / (1/2) = 4 . b. (5^2)^(x-1) + 4. 5^x - 21= 0 (5^x)^2 . 5^-2 + 4. 5^x - 21= 0 5^x = a --> x = 5'log a dengan a >0 1/25 a^2 + 4 a - 21 = 0 a^2 + 100 a - 525 = 0 (a + 105)(a-5) = 0 a = -105 (TM) a = 5 --> x = 1
muzallifahnila30
bgian a bnr a)
misal (√3)^x = a --> x = √3'log a dengan a> 0
7 a - a^2 = - 18
a^2 - 7a - 18 = 0
(a-9)(a+2) = 0
a = 9 atau a= -2 (TM)
x = √3'log 9
x= (3^1/2)'log 3^2
x = (2) / (1/2) = 4
.
misal (√3)^x = a --> x = √3'log a dengan a> 0
7 a - a^2 = - 18
a^2 - 7a - 18 = 0
(a-9)(a+2) = 0
a = 9 atau a= -2 (TM)
x = √3'log 9
x= (3^1/2)'log 3^2
x = (2) / (1/2) = 4
.
b.
(5^2)^(x-1) + 4. 5^x - 21= 0
(5^x)^2 . 5^-2 + 4. 5^x - 21= 0
5^x = a --> x = 5'log a dengan a >0
1/25 a^2 + 4 a - 21 = 0
a^2 + 100 a - 525 = 0
(a + 105)(a-5) = 0
a = -105 (TM)
a = 5 --> x = 1
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