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54][ Fluida
a = air, b = benda, m = minyak
ρa = 1 gr/cm³ → Vm / V = ¼
ρm = 0,8 gr/cm³ → Vm / V = __?
di dalam air
Vm / V = 1 - ρb/ρa
¼ = 1 - ρb/1
ρb = ¾ gr/cm³
di dalam minyak
Vm / V = 1 - ρb/ρm
Vm / V= (1 - ¾/0,8) × 100%
Vm / V = 6,25 % ← jwb
55][ Gaya Listrik
Qa = 10 μC = 10×10⁻⁶ C
Qb = - 10 μC = -10×10⁻⁶ C
Qc = 2 μC = 2×10⁻⁶ C
r = 20 cm = 0,2 m
cos α = 5/20 = ¼
Gaya pada C oleh A
Fca = k Qc Qa / r²
Fca = 9×10⁹ • 2×10⁻⁶ • 10×10⁻⁶ / 0,2²
Fca = 4,5 N menjauhi A
Gaya pada C oleh B
Fcb = k Qc Qb / r²
Fcb = 4,5 N menuju B
Resultan gaya pada C
Fc = Fca cos α + Fcb cos α
Fc = 2 • 4,5 • ¼
Fc = 9/4 = 2,25 N ← jwb