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LM = KM + 4
KEL Δ = 25
PANJANG KL =?
JWB :
KEL Δ = KL + LM + KM
25 = (LM - 1) + (KM + 4) + KM
25 = [ (KM + 4) - 1] + KM + 4 + KM
25 = 3 KM + 7
25 - 7 = 3 KM
18 = 3 KM
18/3 = KM
6 = KM
LM = KM + 4
= 6 + 4 = 10
KL = LM - 1
= 10 - 1 = 9
= (4+x)-1
= 3+x cm
KM = x cm
LM = 4+x cm
maka:
K = 25
KL+LM+KM = 25
3+x+4+x+x = 25
7+3x = 25
3x = 25-7
3x = 18
x = 18/3
x = 6 cm
jadi, KL = 3+x
= 3+6 = 9 cm (C)