Question

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persamaan kuadrat X²+4px+4=0 mempunyai akar akar X1 dan X2. jika X1.X2²+X1².X2=32, nilai p adalah

Answer 1

Verified answer

X1.X2²+X1².X2 = 32
(X1.X2)X2 + X1(X1.X2) = 32
(X1.X2) (X2 + X1) = 32
(C/A) (-B/A) = 32
(4/1) (-4P/1) = 32
(4) (-4P) = 32
-16P = 32
P = 32/-16
P = -2

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