Kelas : IX
Mapel : Matematika
Bab : I - Bilangan Berpangkat
Kode : 9.2.1
[tex] \\ [/tex]
Nomor 1
Sub A
[tex] 3^1+3^0 [/tex]
[tex] = 3+1 [/tex]
[tex] = \boxed{ 4 } [/tex]
Sub B
[tex] (-2)^{-6} [/tex]
[tex] = (2)^{6} [/tex]
[tex] = 2\times 2\times 2\times 2\times 2\times 2 [/tex]
[tex] = \boxed{64} [/tex]
Sub C
[tex] (-3^3)\times (-3)^0 [/tex]
[tex]= (-27)\times 1 [/tex]
[tex]= (-27) [/tex]
[tex]=\boxed{ -27 } [/tex]
Sub D
[tex] \bigg(\dfrac{ 1 }{ 2 } \bigg)^{-3} + \dfrac{7 }{ 8 } [/tex]
[tex]= 2^3 + \dfrac{7 }{ 8 } [/tex]
[tex]= 8 + \dfrac{7 }{ 8 } [/tex]
[tex]= \dfrac{ 64 }{ 8 } + \dfrac{7 }{ 8 } [/tex]
[tex]= \boxed{\dfrac{ 71 }{ 8 } } [/tex]
Sub E
[tex] \dfrac{ 1 }{ 2} + \bigg( - \dfrac{ 2 }{3 }\bigg)^{-2} [/tex]
[tex] = \dfrac{ 1 }{ 2} + \dfrac{ 3^2 }{2^2 } [/tex]
[tex] = \dfrac{ 1 }{ 2} + \dfrac{ 9 }{4 } [/tex]
[tex] = \dfrac{ 2 }{ 4} + \dfrac{ 9 }{4 } [/tex]
[tex] =\boxed{ \dfrac{ 11 }{ 4} } [/tex]
Nomor 2
[tex] 5+3\times 2^4 [/tex]
[tex] = 5+(3\times 2^4) [/tex]
[tex] = 5+(3\times 16) [/tex]
[tex] = \boxed{53 } [/tex]
#TingkatkanPrestasimu
If there is anything you would like to inquire about regarding this answer, please feel free to ask in the comment section. Thank you.
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Kelas : IX
Mapel : Matematika
Bab : I - Bilangan Berpangkat
Kode : 9.2.1
[tex] \\ [/tex]
Nomor 1
Sub A
[tex] 3^1+3^0 [/tex]
[tex] = 3+1 [/tex]
[tex] = \boxed{ 4 } [/tex]
[tex] \\ [/tex]
Sub B
[tex] (-2)^{-6} [/tex]
[tex] = (2)^{6} [/tex]
[tex] = 2\times 2\times 2\times 2\times 2\times 2 [/tex]
[tex] = \boxed{64} [/tex]
[tex] \\ [/tex]
Sub C
[tex] (-3^3)\times (-3)^0 [/tex]
[tex]= (-27)\times 1 [/tex]
[tex]= (-27) [/tex]
[tex]=\boxed{ -27 } [/tex]
[tex] \\ [/tex]
Sub D
[tex] \bigg(\dfrac{ 1 }{ 2 } \bigg)^{-3} + \dfrac{7 }{ 8 } [/tex]
[tex]= 2^3 + \dfrac{7 }{ 8 } [/tex]
[tex]= 8 + \dfrac{7 }{ 8 } [/tex]
[tex]= \dfrac{ 64 }{ 8 } + \dfrac{7 }{ 8 } [/tex]
[tex]= \boxed{\dfrac{ 71 }{ 8 } } [/tex]
[tex] \\ [/tex]
Sub E
[tex] \dfrac{ 1 }{ 2} + \bigg( - \dfrac{ 2 }{3 }\bigg)^{-2} [/tex]
[tex] = \dfrac{ 1 }{ 2} + \dfrac{ 3^2 }{2^2 } [/tex]
[tex] = \dfrac{ 1 }{ 2} + \dfrac{ 9 }{4 } [/tex]
[tex] = \dfrac{ 2 }{ 4} + \dfrac{ 9 }{4 } [/tex]
[tex] =\boxed{ \dfrac{ 11 }{ 4} } [/tex]
[tex] \\ [/tex]
Nomor 2
[tex] 5+3\times 2^4 [/tex]
[tex] = 5+(3\times 2^4) [/tex]
[tex] = 5+(3\times 16) [/tex]
[tex] = \boxed{53 } [/tex]
[tex] \\ [/tex]
#TingkatkanPrestasimu
If there is anything you would like to inquire about regarding this answer, please feel free to ask in the comment section. Thank you.